2(-5x^2-8+8)=0

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Solution for 2(-5x^2-8+8)=0 equation: 



2(-5x^2-8+8)=0

We multiply parentheses

-10x^2-16+16=0

We add all the numbers together, and all the variables

-10x^2=0

a = -10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-10)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-20}=0$

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